Question

Answer the following about NMR analysis of ACETONE:

1. number of signals

2. integration

3. splitting

Answer 1

¹HNMR of acetone:

1) Number of signals: There will be only one signal as all the protons are equivalent.

2) Integration: There is total 6 protons and all protons are equivalent thus the integration will be 6.

3) Splitting: There no protons are available in alfa-carbon. Thus no coupling and splitting is singlet.

¹³HNMR of acetone:

1) Number of signals: There will be only two signal as two types of carbons are present.

2) Integration: For 13C integration is not done.

3) Splitting: There will be no splittting.