Question

Calculate the pH and the pOH of each of the following solutions at 25 degrees Celsius...

Calculate the pH and the pOH of each of the following solutions at 25 degrees Celsius for which the substances ionize completely:

a) 0.200 M HCl

b) 0.0143 M NaOH

c) 3.0 M HNO3

d) 0.031 M Ca(OH2)

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Homework Answers

Answer #1

All are strong acids and bases so they completely dissociate to form ions

1) HCl(aq) -----> H+(aq) + Cl-(aq)

Since HCl and H+ are in 1:1 mole ration

0.200 M HCl give 0.200 M H+ ions

pH = -log[H+]

pH = -log[0.200]

pH = 0.699

pH + pOH = 14

pOH = 14 - pH = 14-0.699

pOH = 13.3

b) NaOH(aq) -----> Na+(aq) + OH- (aq)

NaOH and OH- are 1:1 mole ratio

0.0143 M NaOH gives 0.0143 M OH- ions

pOH = -log[OH-]

pOH = -log(0.0143)

pOH = 1.85

pH + pOH = 14

pH = 14 - pOH

pH = 14 - 1.85

pH = 12.15

C)

HNO3(aq) --------> NO3-(aq) + H+(aq)

HNO3: H+ = 1:1

3.0 M HNO3 gives 3.0 M H+

pH = -log[H+]

pH = - log [3.0]

pH =-0.477

pOH= 14 - pH

pOH = 14 - (-0.477) = 14.5

d) 0.031 M Ca(OH)2

Ca(OH)2(aq) ------------> Ca+2(aq) + 2OH-(aq)

Ca(OH)2 :OH- are in 1:2 mole ratio

Concentration of [OH-] =

pOH = -log[OH-] = -log[0.062]

pOH = 1.2

pH = 14-pOH

pH = 14-1.2

pH =12.8

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