Place the following in order of increasing size: (explain why!!!!)
O2-, F1-, Li1+
these ions are in the same period, that is, same row
then we can compare directly, since if we had different rows the analysis will be more complex
by definition
ions = loss of electrons
Li+ means it is positive charged, it losed 1 electron
then, this is the smallest one, since the electron cloud shrinks due to the abscence of an electron
then comes F-; since it gained 1 electron, the electorn cloud is expanded
finally, comes O2-; which has 2 extra electrons, therefore, ther eis plently of charge to expand it evne more (i.e. O- then O-2)
order of size
O2-> F- > Li+
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