Question

the following are isoelectronic species: N3-, O2-, and Al3+. Rank them in order of increasing

_______<________<__________

Ionization energy

_________<___________<__________

Electron attachment enthaply.

_____<_________<_________

Answer 1

Larger the negative charge on an atom, larger will be size because extra electron cause more repulsion hence ionic size increases, thus size order is : Al³⁺ < O^2- < N^3-

Ionization energy order: it is energy needed to remove an electron.

higher the number of proton at the nucleus , higher will be force of attraction experienced by outermost shell electron being removed. As Al3+ has highest proton and N has minimum among the given spevies. Therefore, order is N^3- < O^2- < Al³⁺

^{electron attachment enthalpy : if added electron is more attracted toward nucleus then attachment enthalpy will be higher, Al3+ has highest number of proton at the nucleus and N3- has mminimum number of proton hence, order of attachment enthalpy will be:}

N^3- < O^2- < Al³⁺