Calculate the following in 7.50 g Li3PO4 a) Li ions b) grams O
Molar mass of Li3PO4 is 115.7944 g/mol
weight of Li3PO4 = 7.5 g
= 7.5 / 115.7944 = 0.0647699 M
1 M compound Li3PO4 having 3 x 6.023 x 1023 Li ions
Hence 0.0647699 M compound having = 6.023 x 1023 x 0.0647699 x 3 = 1.17 x 1023 Li ions
1 M compound Li3PO4 having 4 Oxygen ions which is 64g/mol
Hence 0.0647699 M compound having = 0.0647699 x 64 = 4.14 gm of oxygen is present
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