1)
NaHCO3
MW of Na = 23
MW o fH = 1
MW C = 12
MW O = 16
MW NaHCO3= 84.007
then
% Na = mass of Na/Total Mass * 100 = 23/84.007*100 = 27.3%
% H = mass of H/Total Mass * 100 = 1/84.007*100 = 1.1903%
% C = mass of C/Total Mass * 100 = 12/84.007*100 = 14.284%
% O = mass of O/Total Mass * 100 = 16*3/84.007*100 = 57.1380%
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