Write the electron configurations for the following atoms or ions:
(a) B3+
(b) O–
(c) Cl3+
Boron atom atomic number is 5. Electronic configuration of Boron is 1S22S22P1.
B3+ is formed by the removal of three outer shell electrons from the boron atom (B). Hence the electronic configuration of B3+ is 1S2.
Oxygen atom atomic number is 8. Electronic configuration of Boron is 1S22S22P4.
O- is formed by the addition of one electron to the outer shell of the Oxygen atom (O). Hence the electronic configuration of O- is 1S22S22P4.
Chlorine atom atomic number is 17. Electronic configuration of Boron is 1S22S22P63S23P5.
Cl3+ is formed by the removal of three outer shell electrons from the Chlorine atom (Cl). Hence the electronic configuration of Cl3+ is 1S22S22P63S23P2.
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