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What volume, in liters, of SO2 is formed when 123 L of H2S(g) is burned?

What volume, in liters, of SO2 is formed when 123 L of H2S(g) is burned?

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Answer #1

2H2S + 3O2 -----------> 2SO2 + 2H2O

2 moles of H2S is burned to gives 2 moles of SO2

2*22.4L of H2S is burned to gives 2*22.4L of SO2

123L of H2S is burned to gives = 2*22.4*123/2*22.4   = 123L of SO2 >>>>>answer

                                                    

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