What is the total volume of gaseous products formed when 142 liters of ammonia react completely according to the following reaction? (All gases are at the same temperature and pressure.) ammonia (g) + oxygen(g)nitrogen monoxide (g) + water(g)
______ liters products
All gases are at the same temperature and pressure
so, number of mole is directly propoinal to volume
reaction taking place is
4NH3 + 5O2 --> 4NO + 6H2O
according to reaction
4 L of NH3 give 4 L of NO
1 L of NH3 give 1 L of NO
142 L of NH3 give 142 L of NO
volume of NO formed = 142 L
also,
4 L of NH3 give 6 L of H2O
1 L of NH3 give 6/4 L of H2O
142 L of NH3 give (6/4)*142 L of H2O
volume of H2O formed = 213 L
total volume of product formed = (volume of NO formed)+(volume
of H2O formed)
= 142 + 213
= 355 L
Answer : 355 L
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