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Suppose electrons had a spin of 3/2 instead of 1/2. What would be Z for the...

Suppose electrons had a spin of 3/2 instead of 1/2. What would be Z for the first noble gas? What if electrons instead had spin 1? Explain your reasoning.

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I think the answer for 3/2 is Z=4 since there will be 4 spacial states, but there are conflicting answers from previous cheggs. A clear explanation would be very apprecaited!

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Answer #1

Answer: According to question If electrond had a spin of 3/2 Means it exclusion of Pauling and There is some increase in the magnetic moment and we get the Some different theories of the quantum chemistry . The electrons spin becomes +3/2 and -3/2 .

For the first nobel gas the electronic configuration is 1S2 means total number of electrons are 2 and Atomic number [Z] is also for the first noble gas is 2

Hence this is all about the given question . Thank you .

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