A chloride salt MCl2 is 63.89% chlorine by mass. What is the identity of M?
Please explain steps
Given that;
A chloride salt MCl2 is 63.89% chlorine by mass
Cl has an atomic mass of 35.5 g/mol and given that Cl takes up
63.89% of the total mass of the compound, we can find the total
mass of the compound:
Here two Cl atoms are present.
(35.5 g/mol *2) / total mass of compound =63.89%
(35.5 g/mol *2) / total mass of compound =63.89/100
total mass of compound =35.5 g/mol *2 / 0.6389
total mass of compound = 111.13 g/mol
So the unknown compound has a total mass of 111.13 g/mol. Since we
know that there is 2 Cl atoms the mass of the metal is 111.13 –
71.0 = 40.13 g/mol. Now look on to the periodic table and look for
an element with a mass that is close to 40.13 g/mol, and we see
that it is Ca.
Hence the compound is CaCl2.
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