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If I mixed 10 ml of 2-ethoxyethanol and added 2.6 ml of 2-bromo-2-methylbutane and 2.3 g...

If I mixed 10 ml of 2-ethoxyethanol and added 2.6 ml of 2-bromo-2-methylbutane and 2.3 g of potassium hydroxide and only got 1 g of product, how do I figure the percent yield? I still don't understand that.

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