Question

How do I calculate how much 2,3-dimethyl-1,3-butadiene (d =0.72 g/ml) needs to be added to a reaction with 180 mg maleic acid and 1 mL of polyethylene glycol (molecular weight 200)? It asks to solve for 1.0 equivalent of 2,3-dimethyl-1,3-butadiene.

Answer 1

Molar mass of 2,3-dimethyl-1,3-butadiene is 82 g/mol

MOlar mass of maleic acid is 116 g/mol

1 mole = 116 g of maleic acid reacts with 1 mole=82 g of 2,3-dimethyl-1,3-butadiene

OR

116 mg of maleic acid reacts with 82 mg of 2,3-dimethyl-1,3-butadiene

180 mg of maleic acid reacts with M mg of 2,3-dimethyl-1,3-butadiene

M = ( 180x82) / 116

= 127.2 mg

= 127.2x10^-3 g

So Volume of 2,3-dimethyl-1,3-butadiene required is , V = density x mass

= 0.72 (g/mL) x 127.2x10^-3 g

= 0.092 mL