Question

What mass of oxygen is necessary to burn 176.2 g of propane in a balanced fashion?

What is the theoretical yield of water, in grams?

Answer 1

C3H8   +   5 O2 (g)   ------------> 3 CO2 (g) + 4 H2O (g)

44.1 g       160 g                            132 g             72.08 g

176.2 g      ??

from the balanced equation :

44.1 g C3H8     ---------------> 160 g O2

176.2 g C3H8    --------------->   ??

mass of O2 = 176.2 x 160 / 44.1

mass of oxygen needed = 639.3 g

44.1 g C3H8 ------------->   72.08 g H2O

176.2 g C3H8   ----------->      ??

mass of H2O = 176.2 x 72.08 / 44.1

theoretical yield of water = 288 g