Question

# Propane gas, C3H8, undergoes combustion with oxygen gas to produce carbon dioxide and water gases. Propane...

Propane gas, C3H8, undergoes combustion with oxygen gas to produce carbon dioxide and water gases. Propane has a density of 2.02 g/L at room temperature.

Write the balanced chemical equation.

How many grams of H2O form when 5.50 L of C3H8 reacts?

How many grams of H2O can be produced from the reaction of 170. g of C3H8 ?

Ans :

The balanced chemical equation is given as :

C3H8 + 5O2 = 3CO2 + 4H2O

Density = mass / volume

2.02 = m / 5.50

m = 11.11 g

Number of mol of propane = 11.11 / 44.09562 = 0.252 mol

Each mol propane makes 4 mol water

So number of mol of water produced = 0.252 x 4 = 1.008 mol

Mass of H2O formed = 1.008 x 18.01528

= 18.2 grams

Number of mol of propane = given mass / molar mass

= 170 / 44.09562

= 3.855 mol

Each mol propane makes 4 mol water

So number of moles of H2O = 4 x 3.855 = 15.42 mol

Mass of H2O formed = 15.42 x 18.01528

= 277.8 grams

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