Question

# The next three questions are based on the combustion of propane gas (C3H8) with oxygen to...

The next three questions are based on the combustion of propane gas (C3H8) with oxygen to produce carbon dioxide and water vapor.

C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O(g)

Stu Dent measures exactly 5.10 g of C3H8 and burns it with excess oxygen gas. What is his theoretical yield of carbon dioxide gas?  What is his theoretical yield of water vapor?  (Both answers should have 3 significant digits and units of g)

Stu measures his experimental products. He finds 13.3 g CO2 and 6.94 g H2O formed. What is the percent yield for carbon dioxide?  What is the percent yield for water?  (Both answers should have 3 significant digits with units of %)

Calculate Stu's percent error for his two products. (Both answers should have 3 significant digits with units of %)

Percent error for carbon dioxide?  Percent error for water?

From the reaction

44 g C3H8 produces = 132 g CO2

5.10 g C3H8 produces = 132*5.10/44 = 15.3 g CO2

theoretical yield of carbon dioxide gas = 15.3 g

From the reaction

44 g C3H8 produces = 18*4 = 72 g H2O

5.10 g C3H8 produces = 72*5.10/44 = 8.345 g H2O

theoretical yield of water vapor = 8.345 g

Percent yield of CO2 = actual yield*100/theoretical yield

= 13.3*100/15.3 = 86.928%

Percent yield of H2O = 6.94*100/8.345 = 83.164%

Percent error for CO2 = (15.3-13.3)*100/15.3 = 13.072%

Percent error for H2O =( 8.345-6.94)*100/8.345 = 16.836%

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