Question

Reaction of Al2(SO4)3 solution with NaOH forms a precipitate according to the equation:

Al2(SO4)3(aq) + 6 NaOH (aq) --> 3 Na2SO4 + 2 Al (OH)3

Addition of more NAOH causes the precipiate to redissolve:

Al(OH)3 + NaOH --> NaAl(OH)4(aq)

Describing the reaction above on would state: If one adds NaOH dropwise to Al2(SO4)3 solution, first one would see a ______ with the formula ________. If one continues to add NaOH then one will observe a formation of a ________ with the formula __________

Answer 1

Reaction of Al2(SO4)3 solution with NaOH forms a precipitate according to the equation:

Al2(SO4)3(aq) + 6 NaOH (aq) --> 3 Na2SO4 (aq) + 2 Al (OH)3(s)

Addition of more NAOH causes the precipiate to redissolve:

Al(OH)3 + NaOH --> NaAl(OH)4(aq)

Describing the reaction above on would state:

If one adds NaOH dropwise to Al2(SO4)3 solution, first one would see a precipitate with the formula Al (OH)₃

If one continues to add NaOH then one will observe a formation of a complex with the formula NaAl(OH)₄