balance chemical reaction
2Al(s) + 3H2SO4(aq) ---> Al2(SO4)3(aq) + 3H2(g)
2 mole of Al react with 3 mole of H2SO4 and produce 1 mole of Al2(SO4)3 and 3 mole of H2 gas
a) find moles of Al in 14.2 g block
no. of moles = given mass / molar mass { molar mass Al = 26.98 ~ 27 g/mol}
no. of moles = (14.2 g / 26.98 g/mol) =0.526 moles
2 mole Al need 3 mole of H2SO4
so 0.526 moles of Al need = ?
H2SO4 = 0.526(3/2) = 0.789 moles ~ 0.79 moles
mass of H2SO4 = 0.79 moles x 98.08 g/mol = ~ 77.48 g
B) 2 moles of Al produce 3 moles of H2 gas
moles of H2 gas = 0.79 moles
mass of H2 g = 2g/mol x 0.79 moles = 1.58 g
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