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Sulfuric acid dissolves aluminum metal according to the following reaction: 2Al(s)+3H2SO4(aq)→Al2(SO4)3(aq)+3H2(g) Suppose you wanted to dissolve...

Sulfuric acid dissolves aluminum metal according to the following reaction:

2Al(s)+3H2SO4(aq)→Al2(SO4)3(aq)+3H2(g)

Suppose you wanted to dissolve an aluminum block with a mass of 15.1 g .

What minimum mass of H2SO4 would you need?

What mass of H2 gas would be produced by the complete reaction of the aluminum block?

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Answer #1

according to the reaction

54 grams of aluminium   react with 294 grams of sulphuric acid

15grams of aluminium   react with------------------- ? grams of sulphuric acid

= 15*294/54

= 81.66 grams of sulphuric acid.

54 grams of aluminium react with sulphuric aicd gives ------------------------6 grams of hydrogen

15.1 grams of aluminium react with sulphuric acid gives --------------------- ?

                               = 15.1*6/54

           = 1.67 grams of hydrogen

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