Question

Part A

Benzene, ethane, and ethylene are just three of a large number of hydrocarbons-compounds that contain only carbon and hydrogen. Show how the following data are consistent with the law of multiple proportions.

Compound	Mass of carbon in 5.00 g sample	Mass of hydrogen in 5.00 g sample
Benzene	4.61 g	0.39 g
Ethane	4.00 g	1.00 g
Ethylene	4.29 g	0.71 g

Check all that apply.

Check all that apply.

C:H mass ratio in ethyleneC:H mass ratio in ethane=3/2

C:H mass ratio in benzeneC:H mass ratio in ethylene=3/2

C:H mass ratio in benzeneC:H mass ratio in ethane=3/1

C:H mass ratio in ethyleneC:H mass ratio in ethane=3/1

C:H mass ratio in benzeneC:H mass ratio in ethane=2/3

C:H mass ratio in benzeneC:H mass ratio in ethylene=2/1

C:H mass ratio in benzeneC:H mass ratio in ethylene=2/3

C:H mass ratio in benzeneC:H mass ratio in ethane=1/2

C:H mass ratio in ethyleneC:H mass ratio in ethane=1/2

SubmitMy AnswersGive Up

Answer 1

According to the law of multiple proportions, the compounds are composed of integral multiple of simple proportions. For example:

In benzene we have 6 carbon and 6 hydrogen atoms. So the mass ratio between C and H is 6*12 : 6*1 = 12 : 1.

In ethane we have 2 carbon and 6 hydrogen atoms. So the mass ratio between C and H is 2*12 : 6*1 = 4 : 1

In ethylene we have 2 carbon and 4 hydrogen atoms. So the mass ratio between C and H is 2*12 : 4*1 = 6 : 1

Now, as per the given mass of carbon and hydrogen in the given compounds, the mass ratio will be:

Benzene = 4.61 : 0.39 = 11.82 : 1

12 :1

Ethane = 4 : 1

Ethylene = 4.29 : 0.71 = 6.04 : 1

6 : 1

Hence, the given data are consistent with the law of multiple proportions.