Sulfur and fluorine form several different compounds including
sulfur hexafluoride and sulfur tetrafluoride. Decomposition of a
sample of sulfur hexafluoride produced 4.47 g of fluorine and 1.27
g of sulfur, while decomposition of a sample of sulfur
tetrafluoride produced 4.41 g of fluorine and 1.88 g of
sulfur.
1. Calculate the mass of fluorine per gram of sulfur for the sample
of sulfur hexafluoride
2. Calculate the mass of fluorine per gram of sulfur for the sample
of sulfur tetrafluoride.
3. Show that these results are consistent with the law of multiple proportions.
Express your answers as integers separated by a comma.
1. Calculate the mass of fluorine per gram of sulfur for the sample of sulfur hexafluoride
% F = 4.47/1.27 = 3.51 g of F per g of S
2. Calculate the mass of fluorine per gram of sulfur for the sample of sulfur tetrafluoride.
% F = 4.41/1.88 = 2.345 g of F per g of S
3. Show that these results are consistent with the law of multiple proportions.
these results in theoretical values:
ratio = mass of F / mass of S = 6*18.9 / (32) = 3.54375
ratio = mass of F / mass of S = 4*18.9 / (32) = 2.3625
Those are pretty near to the experimental values calcualted in 1 and 2
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