You have 2 enzymes, A and B that can act of substrate S. Enzyme
A has a higher Km than enzyme B. Which enzymes will be active under
the following conditions:
a) high [S]
b) low [S]
Michaelis–Menten equation is used typically in enzymatic reactions.
V = Vmax*[S] / (Km + [S])
Where
Vmax = max rate velocity
[S] = substrate concentration
Km = Michaelis–Menten constant
V = reaction rate
a)
if [S] high --> V = Vmax*[S] / (Km + [S]) --->
for A (high KM) -> V = Vmax*[S] / (Km + [S])
for B (low Km) --> V = Vmax*[S] / (Km + [S]) = Vmax*[S] / ([S]) = Vmax
therefore, B
b)
low S
for A (high KM) -> V = Vmax*[S] / (Km)
for B (low Km) --> V = Vmax*[S] / (Km + [S]) = Vmax [S]/[S] = Vmax
then A
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