Question

print this pattern in java using one inner and one outer loop.

1

2 1

3 2 1

4 3 2 1

5 4 3 2 1

6 5 4 3 2 1

5 4 3 2 1

4 3 2 1

3 2 1

Answer 1

Program :

class Pattern
{
public static void main(String args[])
{
int r,c;
for(r=1;r<=11;r++)
{
if(r<=6)
{
for(c=r;c>=1;c--)
{
System.out.print(c+" ");
}
}
else
{
for(c=12-r;c>=1;c--)
{
System.out.print(c+" ");
}
}
System.out.println();
}
}
}

Output :

As given the pattern's sample output /structure in your question:

Program :

class Pattern
{
public static void main(String args[])
{
int r,c;
for(r=1;r<=11;r++)
{
if(r<=6)
{
for(c=r;c>=1;c--)
{
System.out.print(c+" ");
}
}
else if(r>6 && r<=9)
{
for(c=12-r;c>=1;c--)
{
System.out.print(c+" ");
}
}
System.out.println();
}
}
}

Output :

Note :

Both the programs are correct just I thought last 2 lines of your sample pattern were missing(intentionally or accidentally) so giving you two programs. first: may you wanted that way or second: you have given intentionally.