Question

How many grams of fluorine are in 24.7 grams of NF3?

Answer #1

Molar mass of NF3,

MM = 1*MM(N) + 3*MM(F)

= 1*14.01 + 3*19.0

= 71.01 g/mol

mass(NF3)= 24.7 g

use:

number of mol of NF3,

n = mass of NF3/molar mass of NF3

=(24.7 g)/(71.01 g/mol)

= 0.3478 mol

This is number of moles of NF3

one mole of NF3 contains 3 mole of F

use:

number of moles of F = 3 * number of moles of NF3

= 3 * 0.3478

= 1.044

Molar mass of F = 19 g/mol

use:

mass of F,

m = number of mol * molar mass

= 1.044 mol * 19 g/mol

= 19.8 g

Answer: 19.8 g

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