Question

What is the mass of 9.09x10^23 atoms of fluorine? grams What is the mass of 8.18x10^23...

What is the mass of 9.09x10^23 atoms of fluorine?

grams

What is the mass of 8.18x10^23 molecules of fluorine?

grams

Homework Answers

Answer #1

According to avogadro's law 1 mole substance contain 6.022 X 1023 atom therefore 9.09 X 1023 atom fluorine =

9.09 X 1023 / 6.022 X 1023 = 1.5 mole of fluorine atom

molar mass of fluorine atom (F) = 18.9984 g/mole then1.5 mole of F = 1.5 X 18.9984 = 28.67 gm

mass of 9.09 X 1023 fluorine atom = 28.67 gm

According to avogadro's law 1 mole substance contain 6.022 X 1023 molecule therefore 8.18 X 1023 molecule fluorine =

8.18 X 1023 / 6.022 X 1023 = 1.358 mole of fluorine molecule

molar mass of fluorine molecule (F2) = 37.997 g/mole then1.358 mole of F2 = 1.358 X 37.997 = 51.61 gm

mass of 8.18 X 1023 fluorine molecule = 51.61 gm

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