Question

What is the mass of 9.09x10^23 atoms of fluorine?

grams

What is the mass of 8.18x10^23 molecules of fluorine?

grams

Answer 1

According to avogadro's law 1 mole substance contain 6.022 X 10²³ atom therefore 9.09 X 10²³ atom fluorine =

9.09 X 10²³ / 6.022 X 10²³ = 1.5 mole of fluorine atom

molar mass of fluorine atom (F) = 18.9984 g/mole then1.5 mole of F = 1.5 X 18.9984 = 28.67 gm

mass of 9.09 X 10²³ fluorine atom = 28.67 gm

According to avogadro's law 1 mole substance contain 6.022 X 10²³ molecule therefore 8.18 X 10²³ molecule fluorine =

8.18 X 10²³ / 6.022 X 10²³ = 1.358 mole of fluorine molecule

molar mass of fluorine molecule (F₂) = 37.997 g/mole then1.358 mole of F₂ = 1.358 X 37.997 = 51.61 gm

mass of 8.18 X 10²³ fluorine molecule = 51.61 gm