Question

How many GRAMS of carbon are present in 3.94 grams of carbon monoxide ?
grams carbon.


How many GRAMS of carbon monoxide can be produced from 3.40 grams of oxygen ?
grams carbon monoxide.

How many GRAMS of iron(II) are present in 1.29 grams of iron(II) nitrate ?
grams iron(II).


How many GRAMS of iron(II) nitrate can be made from 3.42 grams of iron(II) ?
grams iron(II) nitrate.

Answer 1

1)

Carbon monoxide = CO

Molar mass of CO = 12 + 16 = 28 gm/mol

Number of moles of CO = Mass/molar mass = 3.94/28 = 0.14071 moles

Mass of Carbon = number of moles * molar mass = 0.14071 mol * 12 gm/mol = 1.6885 grams = 1.69 grams

2)

Carbon monoxide = CO

Molar mass of CO = 12 + 16 = 28 gm/mol

Number of moles of O = Mass/molar mass = 3.40/16 = 0.2125 moles

Mass of Carbon monoxide produced = number of moles * molar mass = 0.2125 mol * 28 gm/mol = 5.95 grams

3)

Iron (II) Nitrate = Fe(NO3)2

Molar mass of Fe(NO3)2 = 55.85 + (14 + 3 * 16) * 2 = 179.85 grams

Mass of Iron(II) = Mass of Fe/Molar mass of Fe(NO3)2 * 1.29

=> 55.85/179.85 * 1.29

=> 0.4005 grams

4)

Using the above data,

Final answer = 3.42 * 179.85/55.85 = 11.01 grams