Optimum Vol NaOH = 30mL
O.1M NaOH
Calculate grapms KHP you must weight out to react with NaOH present in that volume.
The answer is 0.6121 g KHP. Can someone explain how to find this?
Balanced chemical reaction between KHP and NaOH
NaOH + KHC8H4O4 KNaC8H4O4 + H2O
no. of mole = molarity X volume of solution in liter
no. of mole of NaOH = 0.1 X 0.030 = 0.0030 mole
According to balanced chemical reaction 1 mole of NaOH react with 1 mole of KHP then to react with 0.0030 mole of NaOH required KHP = 0.0030 mole
molar mass of KHP = 204.22 g/mol then 0.0030 mole of KHP = 0.0030 X 204.22 = 0.6126 gm
0.6126 gm of KHP requird to react with 30 ml 0.1M NaOH
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