Question

Please answer parts A-K. Thank you!

Part A

How many mm^3 are in 2.20 ft^3

Part B

A lead ball has a mass of 25 pounds and a density of 11.4 g/cm^3. What is the volume of the ball in ml?

Part C

How many low dose 81 mg aspirin tablets can be made from 25.0 pounds of aspirin?

Part D

How much heat in kJ is needed to raise the temperature of 60.0 gal of water from 25.0°C to 60.0°C? q = mcPT

Part E

Calculate the molar mass of C_2952H4664O_832N812S_8 Fe_4

Part F

What is the mass percent of each element in C_10H_15N?

Part G

How many moles of Cu are in 1.48 x 1025 Cu2 SO4 molecules?

Part H

If the actual amount of Li3PO4 produced in the above reaction is 4.53 grams, what is the percent yield?

Part I

What is the [H] and [OH-] of a solution with a pH of 7.4?

Part J

If an unknown molarity NaOH solution is titrated to a faint pink color with 0.407 g of KHP, what is the concentration of the NaOH?

Part K

Determine the molarity of an HCl solution if a 25.0 ml aliquot of the HCl required 28.9 ml of the NaOH from the previous question to get to a faint pink color.

Answer 1

A) 1 ft^3 = 2.832*10^7 mm^3

So, 2.20 ft^3 = 2.20 * 2.832 * 10^7 = 6.23*10^7 mm^3 ....Answer

B) 1 pounds = 453.952 grams

So, 25 pounds = 25*453.952 = 11339.8 grams

Volume = mass/density = 11339.8/11.4 = 994.72 cm^3

1 cm^3 = 1 ml

SO, 994.72 cm^3 = 994.72 ml ....Answer

C) 25 pounds = 11339.8*10^3 mg  

So, number of tablets = 11339.8*10^3 / 81 = 139997 ....Answer

D) 1 gallon = 3785.412 ml

Density of water = 1 g/ml

So,

Mass of water = 3785.412 grams * 60 = 227125 g

Q = 227125 * 4.184 * (60 - 25) = 33260185 J = 33260.2 KJ ...Answer

E) Molar mass of C2952H4664O832N812S8Fe = 65321.46 g/mol

F) Molar mass C10H15N = 149.233 g/mol

% of C = 80.48%

% of H = 10.13%

% of N = 9.39 %

G) Moles of Cu = 2*1.48*10^25 / 6.023*10^23 = 0.49145*10^2 = 49.145 moles