What is the temperature of a gas inside a 6750 mL balloon filled with 0.546 grams of helium gas? The pressure of the balloon in 157 kPa.
PV = nRT
where:
P is the pressure of the gas = 157 kPa = 1.54947 atm
V is the volume of the gas = 6750 ml = 6.75 Liter
n is the amount of substance of gas (in moles) = 0.546 / 4.002 = 0.1364 Moles
R is gas constant = = 0.0821 L atm K-1 Mol-1
T is the absolute temperature of the gas.= ?
substitute in the equation and calculate the temperatre
PV = nRT
T = PV / nR
T = 1.54947 x 6.75 / 0.0821 x 0.1364
T = 933.74 K
T = 660.59 0C
The temperature of the gas inside is 660.59 0C
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