Question

What is the partial pressure of SO2Cl2 in this mixture? Express your answer in torr using...

What is the partial pressure of SO2Cl2 in this mixture?

Express your answer in torr using three significant figures.

Consider the reaction:

SO2Cl2(g)?SO2(g)+Cl2(g),    Kp=2.91×103 at 298 K


In a reaction at equilibrium, the partial pressure of SO2 is 0.134 torr and that of Cl2 is 0.366 torr .

Homework Answers

Answer #1

Ans :- Partial pressure of SO2 at equilibrium = PSO2Cl2 = 1.69 x 10-5

Explanation :-

Given,

Partial pressure of SO2 at equilibrium = PSO2 = 0.134 torr

Partial pressure of SO2 at equilibrium = PCl2 = 0.366 torr and

Partial pressure of SO2 at equilibrium = PSO2Cl2 = ?

Given reaction is :

SO2Cl2(g) <-------------> SO2(g)+Cl2(g),    Kp = 2.91×103 at 298 K

Now, Expression of Pressure equilibrium constant i.e. Kp is :

Kp= PSO2.PCl2 / PSO2Cl2

Kp= (0.134 ) (0.366) / PSO2Cl2

2.91 x 103 = 0.049044 / PSO2Cl2

PSO2Cl2 = 0.049044 / 2.91 x 103

PSO2Cl2 = 1.69 x 10-5

Hence, Partial pressure of SO2 at equilibrium = PSO2Cl2 = 1.69 x 10-5

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