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Consider the reaction: SO2Cl2(g)⇌SO2(g)+Cl2(g) Kp=2.91×103 at 298 K In a reaction at equilibrium, the partial pressure...

Consider the reaction: SO2Cl2(g)⇌SO2(g)+Cl2(g) Kp=2.91×103 at 298 K In a reaction at equilibrium, the partial pressure of SO2 is 159 torr and that of Cl2 is 285 torr . Part A What is the partial pressure of SO2Cl2 in this mixture?

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Answer #1

Consider reaction, SO2Cl2 (g)   SO 2 (g) + Cl 2 (g)

For above reaction, equilibrium constant is K p = ( P SO 2 ) ( P Cl 2 ) / ( P SO2Cl2 ) = 2.91 10 3

We have , equilibrium partial pressure of SO 2 = 159 torr and equilibrium partial pressure of Cl 2 = 285 torr

( 159 ) ( 285 ) / ( P SO2Cl2 ) = 2.91 10 3

( P SO2Cl2 ) = ( 159 ) ( 285 ) / 2.91 10 3

( P SO2Cl2 ) = 15.57 torr

ANSWER : Partial pressure of SO2Cl2 at equilibrium is 15.57 torr​​​​​​​

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