Consider the following reaction:
SO2Cl2(g)⇌SO2(g)+Cl2(g)
A reaction mixture is made containing an initial [SO2Cl2] of
2.2×10−2 M . At equilibrium, [Cl2]=1.0×10−2 M
.
Calculate the value of the equilibrium constant (Kc).
Express your answer using two significant figures.
Given reaction is:
SO2Cl2(g)⇌SO2(g)+Cl2(g)
Initially
[SO2Cl2] = 2.2×10−2 M
At equilibrium,
[Cl2]=1.0×10−2 M.
ICE
SO2Cl2(g)⇌ SO2(g) + Cl2(g)
I 2.2E-2 0 0
C -x +x +x
E (2.2E-2-x) x x = 1.0 E-2
Lets find all the concentrations at equilibrium
[SO2Cl2] =[ 2.2×10−2 – 1.0 E-2 ] M = 1.2 E-2 M
[SO2]= 1.0 E-2
Kc = [SO2][Cl2]/[SO2Cl2]
Kc = (1.0E-2)2 / (1.2E-2)
=0.0083
Kc = 8.3E-3
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