Question

find y(t) solution of the initial value problem

y'=(2y^2 +bt^2)/(ty), y(1)=1 t>o

Answer #1

Find the solution of the given initial value problem.
ty′+3y=t2−t+5, y(1)=5, t>0

For 2y' = -tan(t)(y^2-1) find general solution (solve for y(t))
and solve initial value problem y(0) = -1/3

Find y(t) solution of the initial value problem
3ty^2y'-6y^3-4t^2=0, y(1)=1, t>0

Find a general solution to the given equation for t<0
y"(t)-1/ty'(t)+5/t^2y(t)=0

y′′(t) +ty′(t)−2y(t) = 2, y(0) = 0,y′(0) = 0 . This is a
non-homogeneous linear second-order differential equation
withnon-constantcoefficients andnotof Euler type.
(a) Write the Laplace transform of the Initial Value Problem
above.
(b) Find a closed formula for the Laplace transformL(y(t)).
(c) Find the unique solutiony(t) to the Initial Value
Problem

For the initial value problem
• Solve the initial value problem.
y' = 1/2−t+2y withy(0)=1

for the given initial value problem: (2-t)y' + 2y
=(2-t)3(ln(t)) ; y(1) = -2
solve the initial value problem

Solve the Initial Value Problem:
dydx+2y=9,
y(0)=0
dydx+ycosx=5cosx,
y(0)=7d
Find the general solution, y(t)y(t), which solves the problem
below, by the method of integrating factors.
8tdydt+y=t3,t>08tdydt+y=t3,t>0
Put the problem in standard form.
Then find the integrating factor,
μ(t)=μ(t)= ,__________
and finally find y(t)=y(t)= __________ . (use C as the
unkown constant.)
Solve the following initial value problem:
tdydt+6y=7ttdydt+6y=7t
with y(1)=2.y(1)=2.
Put the problem in standard form.
Then find the integrating factor, ρ(t)=ρ(t)= _______ ,
and finally find y(t)=y(t)= _________ .

solve the given initial value problem. y(cos2t)e^ty -
2(sin2t)e^ty + 2t + (t(cos2t)e^ty - 3) dy/dt = 0, y(0)=0

Find the solution of the given initial value problem:
y(4)+2y′′+y=5t+2; y(0)=y′(0)=0, y′′(0)=y'''(0)=1

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