Question

solve the given initial value problem. y(cos2t)e^ty - 2(sin2t)e^ty + 2t + (t(cos2t)e^ty - 3) dy/dt...

solve the given initial value problem. y(cos2t)e^ty - 2(sin2t)e^ty + 2t + (t(cos2t)e^ty - 3) dy/dt = 0, y(0)=0

Homework Answers

Answer #1

Doubt in any step then comment below. I will explain you.

.

Please thumbs up for this solution. Thanks...

.

Here this equation is exact differential equation , we easily show this ..

Answer is in last closed bracket....

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Solve the initial value problem t^(13) (dy/dt) +2t^(12) y =t^25 with t>0 and y(1)=0 (y'-e^-t+4)/y=-4, y(0)=-1
Solve the initial value problem t^(13) (dy/dt) +2t^(12) y =t^25 with t>0 and y(1)=0 (y'-e^-t+4)/y=-4, y(0)=-1
1. Solve the given initial value problem. dy/dt = (t^3 + t)/(y^2); y(0) = 2 ....
1. Solve the given initial value problem. dy/dt = (t^3 + t)/(y^2); y(0) = 2 . 2. We know from Newton’s Law of Cooling that the rate at which a cold soda warms up is proportional to the difference between the ambient temperature of the room and the temperature of the drink. The differential equation corresponding to this situation is given by y' = k(M − y) where k is a positive constant. The solution to this equation is given...
Solve the initial value problem 8(t+1)dy/dt - 6y = 12t for t > -1 with y(0)...
Solve the initial value problem 8(t+1)dy/dt - 6y = 12t for t > -1 with y(0) = 7 7 =
Solve the initial value problem 8(t+1)dy/dt−6y=12t, for t>−1 with y(0)=11.
Solve the initial value problem 8(t+1)dy/dt−6y=12t, for t>−1 with y(0)=11.
Find the general solution to the given differential equation. 1+(1+ty)e^ty+(1+t^2e^ty) dy/dt=0
Find the general solution to the given differential equation. 1+(1+ty)e^ty+(1+t^2e^ty) dy/dt=0
1. Solve the following initial value problem using Laplace transforms. d^2y/dt^2+ y = g(t) with y(0)=0...
1. Solve the following initial value problem using Laplace transforms. d^2y/dt^2+ y = g(t) with y(0)=0 and dy/dt(0) = 1 where g(t) = t/2 for 0<t<6 and g(t) = 3 for t>6
1)Consider the following initial-value problem. (x + y)2 dx + (2xy + x2 − 2) dy...
1)Consider the following initial-value problem. (x + y)2 dx + (2xy + x2 − 2) dy = 0,   y(1) = 1. Let af/ax = (x + y)2 = x2 + 2xy + y2. Integrate each term of this partial derivative with respect to x, letting h(y) be an unknown function in y. f(x, y) =   + h(y) Solve the given initial-value problem. 2) Solve the given initial-value problem. (6y + 2t − 3) dt + (8y + 6t − 1) dy...
1)  Consider the following initial-value problem. (x + y)2 dx + (2xy + x2 − 2) dy...
1)  Consider the following initial-value problem. (x + y)2 dx + (2xy + x2 − 2) dy = 0,   y(1) = 1 Let af/ax = (x + y)2 = x2 + 2xy + y2. Integrate each term of this partial derivative with respect to x, letting h(y) be an unknown function in y. f(x, y) =    + h(y) Find the derivative of h(y). h′(y) = Solve the given initial-value problem. 2) Solve the given initial-value problem. (6y + 2t − 3) dt...
solve the given initial value problem dx/dt=7x+y x(0)=1 dt/dt=-6x+2y y(0)=0 the solution is x(t)= and y(t)=
solve the given initial value problem dx/dt=7x+y x(0)=1 dt/dt=-6x+2y y(0)=0 the solution is x(t)= and y(t)=
Initial value problem : Differential equations: dx/dt = x + 2y dy/dt = 2x + y...
Initial value problem : Differential equations: dx/dt = x + 2y dy/dt = 2x + y Initial conditions: x(0) = 0 y(0) = 2 a) Find the solution to this initial value problem (yes, I know, the text says that the solutions are x(t)= e^3t - e^-t and y(x) = e^3t + e^-t and but I want you to derive these solutions yourself using one of the methods we studied in chapter 4) Work this part out on paper to...