Question

Please solve the listed initial value problem:

y'' + 3y' + 2y = 1 - u(t - 10); y(0) = 0, y'(0) = 0

Answer #1

Solve the given initial-value problem.
2y'' + 3y' −
2y = 10x2 −
4x − 15, y(0) = 0,
y'(0) = 0

solve the initial value problem y''-2y'+5y=u(t-2) y(0)=0
y'(0)=0

Solve the initial value problem
3y'(t)y''(t)=16y(t) , y(0)=1,
y'(0)=2

For the initial value problem
• Solve the initial value problem.
y' = 1/2−t+2y withy(0)=1

For 2y' = -tan(t)(y^2-1) find general solution (solve for y(t))
and solve initial value problem y(0) = -1/3

Use Laplace transform to solve the following initial value
problem: y '' − 2y '+ 2y = e −t , y(0) = 0 and y ' (0) =
1
differential eq

for the given initial value problem: (2-t)y' + 2y
=(2-t)3(ln(t)) ; y(1) = -2
solve the initial value problem

Solve the initial value problem below for the Cauchy-Euler
equation
t^2y"(t)+10ty'(t)+20y(t)=0, y(1)=0, y'(1)=2
y(t)=

Solve the initial value problem: y′′−2y′+11y=0y″−2y′+11y=0,
y(0)=3y(0)=3, y′(0)=−3.y′(0)=−3.Give your answer as y=... y=... .
Use xx as the independent variable.

Use Laplace transforms to solve the given initial value
problem.
y"-2y'+5y=1+t y(0)=0 y’(0)=4

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