Question

A data set includes 106 body temperatures of healthy adult humans having a mean of 98.7degreesF and a standard deviation of 0.66degreesF. Construct a 99% confidence interval estimate of the mean body temperature of all healthy humans. What does the sample suggest about the use of 98.6degreesF as the mean body temperature? Click here to view a t distribution table.LOADING... Click here to view page 1 of the standard normal distribution table.LOADING... Click here to view page 2 of the standard normal distribution table.LOADING... What is the confidence interval estimate of the population mean mu? nothingdegreesFless thanmuless than nothingdegreesF (Round to three decimal places as needed.)

Answer #1

Solution :

degrees of freedom = n - 1 = 106 - 1 = 105

t/2,df = t0.005,105 = 2.623

Margin of error = E = t/2,df * (s /n)

= 2.623 * (0.66 / 106)

Margin of error = E = 0.168

The 99% confidence interval estimate of the population mean is,

- E < < + E

98.7 - 0.168 < < 98.7 + 0.168

( 98.532 < < 98.868 )

This suggests that the mean body temperature could very possibly 98.6 degrees F.

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