Question

A manufacturer claims that the calling range (in feet) of its 900-MHz cordless telephone is greater than that of its leading competitor. A sample of 11 phones from the manufacturer had a mean range of 1050 feet with a standard deviation of 40 feet. A sample of 18 similar phones from its competitor had a mean range of 1030 feet with a standard deviation of 25 feet. Do the results support the manufacturer's claim? Let µ1 be the true mean range of the manufacturer's cordless telephone and µ2 be the true mean range of the competitor's cordless telephone. Use a significance level of α = 0.01 for the test. Assume that the population variances are equal and that the two populations are normally distributed.

Step 1 of 4: State the null and alternative hypotheses for the test.

Step 2 of 4: Compute the value of the t test statistic. Round your answer to three decimal places.

Step 3 of 4: Determine the decision rule for rejecting the null hypothesis H0. Round your answer to three decimal places.

Step 4 of 4: State the test's conclusion.

Answer 1

To Test :-

H0 :-

H1 :-

Test Statistic :-





t = 1.664

Test Criteria :-
Reject null hypothesis if  


Result :- Fail to Reject Null Hypothesis

Conclusion :- Accept Null Hypothesis

There is no sufficient evidence to support the claim that the calling range (in feet) of its 900-MHz cordless telephone is greater than that of its leading competitor at 1% level of significance.