The average age of passenger train cars is 19.4 years. If the distribution of ages is normal and 14% of the cars are older than 22.7 years, find the standard deviation.
solution:
Let X be the normal random variable representing the age of car
Given that
The average age of cars = = 19.4 years
Probability of cars older than 22.7 years = P(X>22.7) = 0.14
= 0.14
= 0.14
= 0.14
= 0.14
= 0.86
= 1.0805 [ use standard Normal distribution table]
= 3.3 / 1.0805
= 3.05
Required Standard Deviation () = 3.05 years
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