The average age of passenger train cars is 19.4 years. If the distribution of ages is normal and 15% of the cars are older than 21.1 years, find the standard deviation. Round z-value calculations to 2 decimal places and final answer to 2 decimal places.
Solution:-
Given that,
mean = = 19.4
x = 21.1
Using standard normal table,
P(Z > z) = 15%
= 1 - P(Z < z) = 0.15
= P(Z < z) = 1 - 0.15
= P(Z < z ) = 0.85
= P(Z < 1.04 ) = 0.85
z = 1.04
Using z-score formula,
x = z * +
21.1 = 1.04 * + 19.4
= 21.1 - 19.4 / 1.04
= 1.63
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