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The owner of a fish market has an assistant who has determined that the weights of...

The owner of a fish market has an assistant who has determined that the weights of catfish are normally distributed with a mean of 3.2 pounds and a standard deviation of .8 pounds. What is the probability that a sample of 64 fish will have a sample mean between 2.9 and 3.4 pounds?

Math   Statistics-And-Probability   
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Answer #1

Solution :

Given that,

= / n = .8 / 64 = 0.1

= P[(2.9 - 3.2) / 0.1< ( - ) / < (3.4 - 3.2) / 0.1)]

= P(-3 < Z < 2)

= P(Z < 2) - P(Z < -3)

= 0.9772 - 0.0013

= 0.9759

Probability = 0.9759   

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