Question

The owner of a fish market has an assistant who has determined that the weights of catfish are normally distributed, with a mean of 3.2 pounds and a standard deviation of 0.8 pound. If a sample of 16 fish is taken, what would the standard error of the mean weight equal?

		0.003
		0.200
		0.800
		0.050

Answer 1

Solution :

Given that,

mean = = 3.2

standard deviation = = 0.8

n = 16

The standard error of the mean weight equal

= / n = 0.8 / 16 = 0.8 / 4 = 0.200

The standard error of the mean weight equal = 0.200