Suppose you are given a sample of 106 body temperatures having a mean of 98.2oF and a standard deviation of 0.62oF. What is a 95% confidence interval around the true population mean body temperature?
Solution :
Given that,
Z/2
= 1.96
Margin of error = E = Z/2*
(
/
n)
= 1.96 * (0.62 /
106)
= 0.12
At 95% confidence interval estimate of the population mean is,
- E <
<
+ E
98.2 - 0.12 <
< 98.2 + 0.12
98.08 <
< 98.32
(98.08 , 98.32)
Get Answers For Free
Most questions answered within 1 hours.