Question
Suppose you are given a sample of 106 body temperatures having a mean of 98.2oF and...
Suppose you are given a sample of 106 body temperatures having a mean of 98.2oF and a standard deviation of 0.62oF. What is a 95% confidence interval around the true population mean body temperature?
Homework Answers
Answer #1
Solution :
Given that,
Z
/2
= 1.96
Margin of error = E = Z/2*
(
/
n)
= 1.96 * (0.62 /
106)
= 0.12
At 95% confidence interval estimate of the population mean is,
- E < 
<
+ E
98.2 - 0.12 <
< 98.2 + 0.12
98.08 <
< 98.32
(98.08 , 98.32)
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