Question

Suppose you are given a sample of 106 body temperatures having a
mean of 98.2^{o}F and a standard deviation of
0.62^{o}F. What is a 95% confidence interval around the
true population mean body temperature?

Answer #1

Solution :

Given that,

Z_{/2}
= 1.96

Margin of error = E = Z_{/2}*
(
/n)

= 1.96 * (0.62 / 106)

= 0.12

At 95% confidence interval estimate of the population mean is,

- E < < + E

98.2 - 0.12 < < 98.2 + 0.12

98.08 < < 98.32

**(98.08 , 98.32)**

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