Question

A data set includes:

104 body temperatures of healthy adult humans having a mean of

98.798.7 degrees°F

and a standard deviation of

0.660.66 degrees°F.

Construct a 9999​% confidence interval estimate of the mean body temperature of all healthy humans. What does the sample suggest about the use of

98.6 degrees°F as the mean body​ temperature?

What is the confidence interval estimate of the population mean μ​?

​(Round to three decimal places as​ needed.)

Answer 1

df = n - 1 = 104 - 1 = 103

t critical value at 0.01 level with 103 df = 2.624

99% confidence interval for is

- t * S / sqrt(n) < < + t * S / sqrt(n)

98.7 - 2.624 * 0.66 / sqrt(104) < < 98.7 + 2.624 * 0.66 / sqrt(104)

98.530 < < 98.970

99% CI is ( 98.530 , 98.970 )

Claimed temperature 98.6 included in confidence interval.