A population has mean μ = 19 and standard deviation σ = 5. A random sample of size n = 64 is selected. What is the probability that the sample mean is less than 18?
Solution :
= / n = 5 / 64 = 0.625
P( < 18) = P(( - ) / < (18 - 19) / 0.625)
= P(z < -1.6)
= 0.0548
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