Assume that women's heights are normally distributed with a mean given by u equals 64.2 inμ=64.2 in, and a standard deviation given by σ=2.7 in.
(a) If 1 woman is randomly selected, find the probability that her height is less than 65 in.
(b) If 45 women are randomly selected, find the probability that they have a mean height less than 65 in.
Solution :
Given that ,
mean = = 64.2
standard deviation = = 2.7
(a)
P(x < 65) = P[(x - ) / < (65 - 64.2) / 2.7]
= P(z < 0.2963)
= 0.6165
Probability = 0.6165
(b)
= / n = 2.7 / 45 = 0.4025
P( < 65) = P(( - ) / < (65 - 64.2) / 0.4025)
= P(z < 1.9876)
= 0.9766
Probability = 0.9766
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