Question

Assume that women's heights are normally distributed with a mean of 45.7 inches and a standard deviation of 2.25 inches. If 900 women are randomly selected, find the probability that they have a mean height between 45 inches and 45.6 inches.

Answer #1

Given,

= 45.7 , = 2.25

Using central limit theorem,

P( < x) = P( Z < x - / ( / sqrt(n) ) )

P( 45 < < 45.6) = P( < 45.6) - P( < 45)

= P( Z < 45.6 - 45.7 / 2.25 / sqrt(900) - P( Z < 45 - 45.7 / 2.25 / sqrt(900)

= P( Z < -1.3333) - P( Z < -9.3333)

= 0.0912 - 0

= **0.0912**

Assume that women's heights are normally distributed with a mean
of 63.6 inches and standard deviation of 3 inches. If 36 woman are
randomly selected, find the probability that they have a mean
height between 63.6 and 64.6 inches.

Assume that the heights of women are normally distributed with a
mean of 63.6 inches and a standard deviation of 2.5 inches. a) Find
the probability that if an individual woman is randomly selected,
her height will be greater than 64 inches. b) Find the probability
that 16 randomly selected women will have a mean height greater
than 64 inches.

assume that women’s heights are normally distributed with a mean
of 63.6 inches and a standard deviation of 2.5 inches. If 90 women
are randomly selected, find the probability that they have a mean
height between 62.9 inches and 64.0 inces.
extensive step by step of how to solve this plus equation
explanation

Assume that women's heights are normally distributed with a
mean given by u equals 64.2 inμ=64.2 in, and a standard deviation
given by σ=2.7 in.
(a) If 1 woman is randomly selected, find the probability that
her height is less than 65 in.
(b) If 45 women are randomly selected, find the probability
that they have a mean height less than 65 in.

Assume that women's heights are normally distributed with a
mean given by
μ=63.6 in,
and a standard deviation given by
σ=2.7 in.
(a) If 1 woman is randomly selected, find the probability that
her height is less than 64 in.
(b) If 47 women are randomly selected, find the probability
that they have a mean height less than 64 in.

Assume that women's heights are normally distributed with a
mean given by mu equals 62.6 in, and a standard deviation given by
sigma equals 1.9 in. (a) If 1 woman is randomly selected, find
the probability that her height is less than 63 in. (b) If 41
women are randomly selected, find the probability that they have a
mean height less than 63 in.

Assume that women's heights are normally distributed with a mean
given by mu = 64.2in and a standard deviation given by sigma = 2.4
in
(a)
1 woman is randomly selected, find the probability that her is less
than 65 in.
(b)
33 women are randomly selectedfind the probability that they have a
mean height less than 65 in.

Assume that the heights of men are normally distributed with a
mean of 70.8 inches and a standard deviation of 4.5 inches. If 45
men are randomly selected, find the probability that they have a
mean height greater than 72 inches.
(Round
your answer to three decimal
places.)

Assume that women's heights are normally distributed with a
mean given by mu equals 64.8 inμ=64.8 in, and a standard deviation
given by sigma equals 2.7 in σ=2.7 in.
If 7 women are randomly selected, find the probability that
they have a mean height between 64.4 in and 65.4 in.

Assume that women's heights are normally distributed with a
mean given by mu equals 63.4 in, and a standard deviation given by
sigma equals 2.7 in. (a) If 1 woman is randomly selected, find
the probability that her height is less than 64 in. (b) If 36
women are randomly selected, find the probability that they have a
mean height less than 64 in. (a) The probability is approximately
nothing. (Round to four decimal places as needed.)

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