Question

1. TV Watching (Independent Samples t, unequal variances – traditional)

Based on the sample statistics below, is there sufficient evidence to conclude a difference in the average amount of television watching times between the two groups? α = 0.01?

	Children	Teens
n	15	15
M	22.45	18.50
s	16.4	18.2

Step 1: State the hypotheses.

Step 2: Compute the df, Determine the tailed-ness, and Find the Critical Value

Step 3: Compute the test value.

Step 4: Make the decision.

Step 5: Summarize the results.

Answer 1

To Test :-

H0 :-  

H1 :-  

Test Statistic :-


t = 0.6244

Test Criteria :-
Reject null hypothesis if | t | > t(α/2, DF)


Degree of Freedom = 27

Critical value t(α/2, DF) = t(0.01 /2, 27 ) = 2.771
| t | > t(α/2, DF) = 0.6244 < 2.771
Result :- Fail to Reject Null Hypothesis

Decision based on P value
P - value = P ( t > 0.6244 ) = 0.5376
Reject null hypothesis if P value < α = 0.01 level of significance
P - value = 0.5376 > 0.01 ,hence we fail to reject null hypothesis
Conclusion :- We Accept H0

There is insufficient evidence to support the claim that difference in the average amount of television watching time between two groups.