Assume that adults have IQ scores that are normally distributed with a mean of
100.7100.7
and a standard deviation
19.419.4.
Find the first quartile
Upper Q 1Q1,
which is the IQ score separating the bottom 25% from the top 75%. (Hint: Draw a graph.)
The first quartile is
nothing.
(Type an integer or decimal rounded to one decimal place as needed.)
Given,
= 100.7 , = 19.4
We convert this to standard normal as
P(X < x) = P(Z < ( x - ) / )
We have to calculate x such that P(X < x) = 0.25
That is
P(Z < ( x - ) / ) = 0.25
From Z table, z-score for the probability of 0.25 is -0.6745
( x - ) / = -0.6745
( x - 100.7) / 19.4 = -0.6745
Solve for x
x = 87.6
Q1 = 87.6
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