Question

NFL Salaries (Independent Samples t – unequal variances – traditional) An agent claims there is no...

  1. NFL Salaries (Independent Samples t – unequal variances – traditional)

An agent claims there is no difference between the pay of safeties and linebackers in the NFL. Is there a significant difference in salaries, at α = 0.05.

Safeties

Linebackers

n

15

15

M

$501,580

$513,360

S

$20,000

$18,000

Step 1: State the hypotheses.

Step 2: Compute the df, Determine the tailed-ness, and Find the Critical Value

Step 3: Compute the test value.

Step 4: Make the decision.

Step 5: Summarize the results.

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
TV Watching (Independent Samples t, unequal variances – traditional) Based on the sample statistics below, is...
TV Watching (Independent Samples t, unequal variances – traditional) Based on the sample statistics below, is there sufficient evidence to conclude a difference in the average amount of television watching times between the two groups? α = 0.01? Children Teens n 15 15 M 22.45 18.50 s 16.4 18.2 Step 1: State the hypotheses. Step 2: Compute the df, Determine the tailed-ness, and Find the Critical Value Step 3: Compute the test value. Step 4: Make the decision. Step 5:...
Cholesterol Levels (Dependent Samples t – traditional) A doctor wishes to see if men’s cholesterol levels...
Cholesterol Levels (Dependent Samples t – traditional) A doctor wishes to see if men’s cholesterol levels will change if they alter their exercise routine to include weight training. Six subjects were pretested and then changed their exercise routine for 6 weeks. The results are provided in the table below. Can it be concluded that the cholesterol level has been changed at α = 0.05? Assume the variable is approximately normally distributed. Subject 1 2 3 4 5 6 Before (X1)...
Question 3: Independent-Samples t-Test Group Statistics type of school N Mean Std. Deviation Std. Error Mean...
Question 3: Independent-Samples t-Test Group Statistics type of school N Mean Std. Deviation Std. Error Mean reading score public 168 51.8452 10.42279 .80414 private 32 54.2500 9.19677 1.62578 Independent Samples Test Levene's Test for Equality of Variances t-test for Equality of Means F Sig. t df Sig. (2-tailed) Mean Difference Std. Error Difference 95% Confidence Interval of the Difference Lower Upper reading score Equal variances assumed .564 .453 -1.217 198 .225 -2.40476 1.97519 -6.29986 1.49034 Equal variances not assumed -1.326...
Given two independent random samples with the following results: n1=653   x1=355      n2=597 x2=201 Can it...
Given two independent random samples with the following results: n1=653   x1=355      n2=597 x2=201 Can it be concluded that there is a difference between the two population proportions? Use a significance level of α=0.05 for the test. Step 1 of 6: State the null and alternative hypotheses for the test. Step 2 of 6: Find the values of the two sample proportions, p^1 and p^2. Round your answers to three decimal places. Step 3 of 6: Compute the weighted estimate...
Given two independent random samples with the following results: n1=428 x1=270   n2=251 x2=135 Can it be...
Given two independent random samples with the following results: n1=428 x1=270   n2=251 x2=135 Can it be concluded that there is a difference between the two population proportions? Use a significance level of α=0.05 for the test. Step 1 of 6: State the null and alternative hypotheses for the test Step 2 of 6: Find the values of the two sample proportions, pˆ1 and pˆ2. Round your answers to three decimal places. Step 3 of 6: Compute the weighted estimate of...
Given two independent random samples with the following results: n1=469 x1=250 n2=242 x2=95 Can it be...
Given two independent random samples with the following results: n1=469 x1=250 n2=242 x2=95 Can it be concluded that there is a difference between the two population proportions? Use a significance level of α=0.05 for the test. Step 1 of 6: State the null and alternative hypotheses for the test. Step 2 of 6: Find the values of the two sample proportions, pˆ1p^1 and pˆ2p^2. Round your answers to three decimal places. Step 3 of 6: Compute the weighted estimate of...
Given two independent random samples with the following results: n1 = 226 ^p1 = 0.55 n2...
Given two independent random samples with the following results: n1 = 226 ^p1 = 0.55 n2 = 444 ^p2 = 0.63 Can it be concluded that the proportion found in Population 2 exceeds the proportion found in Population 1?  Use a significance level of α=0.1 for the test. Step 1 of 5: State the null and alternative hypotheses for the test. Step 2 of 5: Compute the weighted estimate of p, p‾. Round your answer to three decimal places. Step 3...
A researcher used a one-factor ANOVA for independent samples to test the effectiveness of four teaching...
A researcher used a one-factor ANOVA for independent samples to test the effectiveness of four teaching methods for autistic children. The experiment was conducted with four samples of n = 12 autistic children in each group. The results of the analysis are shown in the following summary table. Source SS df MS Between Treatments ____ ____ ____ F = 5.00 Within Treatments 88 ____ ____ Total ____ ____ A. Fill in all missing values in the table. Show your work...
Given two independent random samples with the following results: n1=573, p^1=0.5  n2=454, pˆ2=0.6 Can it be...
Given two independent random samples with the following results: n1=573, p^1=0.5  n2=454, pˆ2=0.6 Can it be concluded that the proportion found in Population 2 exceeds the proportion found in Population 1?  Use a significance level of α=0.1α=0.1for the test. Step 1 of 5: State the null and alternative hypotheses for the test. Step 2 of 5: Compute the weighted estimate of p, p‾p‾. Round your answer to three decimal places. Step 3 of 5: Compute the value of the test statistic....
Independent random samples of newly completed apartments in four regions of a country yielded the data...
Independent random samples of newly completed apartments in four regions of a country yielded the data on monthly​ rents, in​ dollars and the summary statistics is given below: Region n Mean Std.deviation MW 6 752.33 89.37 NE 5 1051 146.10 S 4 862.25 159.37 W 5 1055.60 122.62 Do the data provide sufficient evidence to conclude that a difference exists in mean monthly rents among newly completed apartments in the four​ regions? A partially filled in ANOVA table is presented...