Determine Z and X values for a given probability. Z is standard normal, X is normal.
Given
μ = 12 (Units not given)
σ = 3.2 (Units not given)
The probability in the upper tail is:
α = 0.095 (Unitless)
Determine the Z Value associated with the probability and calculate the X Value associated with the Z value.
Given that, mean = 12 and standard deviation = 3.2
We want to find, z-score such that,
P(Z > z) = 0.095
=> 1 - P(Z < z) = 0.095
=> P(Z < z) = 0.905
Using standard normal z-table we get, z-score corresponding probability 0.905 is z = 1.31
=> Z = 1.31
=> X = 16.192
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